laboratory assignment laboratory techniques answers

laboratory assignment laboratory techniques answers

Laboratory Techniques and Measurements

Hands-On Labs, Inc. Version 42-0165-00-02


Lab Report Assistant

This report is not intended to replace an official laboratory report. The Lab Report Assistant is just a summarization of the questions, diagrams (where necessary), and data tables that are to be answered in a formal lab report. The goal is to enable students to write lab reports by simply providing this information in an editable file, which could be sent to an instructor.

Exercise 1: Length, Temperature, and Mass

Data Table 1. Length Measurements.

ObjectLength (cm)Length (mm)Length (m)
CD or DVD18 cm180 mm0.18 m
Key5 cm50 mm0.05 m
Spoon21 cm210 mm0.21 m
Fork15 cm150 mm0.15 m

DataTable2. Temperature Measurements.

WaterTemperature(°C)Temperature(°F)Temperature(K)
Hot from the tap34o C95o F308 K
Boiling97°C209°F367.15 K
Boiling for 5 minutes104°C218°F494 K
Cold from the tap16°C57°F287.15 K
Ice water – 1 minute11°C49°F282.15
Ice water – 5 minutes5°C41°F278.15 K
Data Table 3. Mass Measurements.
ObjectEstimated Mass (g)Actual Mass (g)Actual mass (kg)
Pen or pencil7g9g0.009 kg
3 Pennies7.5 g7.5g0.0075 kg
1 Quarter4 g5.7g0.0057 kg
2 Quarters, 3 Dimes15 g18.2g0.0182 kg
4 Dimes, 5 Pennies20 g22.1 g0.0221 kg
3 Quarters, 1 Dime, 5 Pennies30 g32.60.0326 kg
Key6.5 g7.40.0074 kg
Key, 1 Quarter, 4 Pennies19.6 g23.10.0231 kg


Questions

  1. At sea level, fresh water boils at 100 °C. Had the water in this experiment not boiled when it was put into a 100 °C environment, what might be the explanation?

**The boiling point of water is 100 °C in seawater. The water will boil at a lower temperature when at a level higher than the sea level because there is less pressure. When the water is lower than the sea level, it will boil at a higher temperature than 100 °C since it will be under increased air pressure.

  1. During the time of heating two different samples of water at sea level, one of them will boil at 102 o C, and the other will boil at 99.2 °C. Divide the difference between the theoretically calculated 100.0 o C and the experimental results (percent error) in each sample.

**The sample one with the boiling point of 102 degrees of celesials has the percent error of 2 percent. The percent error of sample two, which has a boiling point of 99.2 degrees Celsius, is -0.8 percent.

Exercise 2: Volume and Density

Data Table 4. Liquid Measurements.

  Mass AMass BMass B – A  
LiquidVolume (mL)Graduated Cylinder (g)Graduated Cylinder withliquid (g)Liquid (g)Density g/mL% Error
Water5.0 ml5.0 ml5.0 ml5.0 ml5.0 ml5.0 ml
Isopropyl alcohol19.4 g19.4 g19.4 g19.4 g19.4 g19.4 g

Data Table 5. Magnet – Measurement Method.

Object:Mass (g)Length (cm)Width (cm)Height (cm)Volume (cm3)Density (g/cm3)
Magnet4 g2.5 cm0.25 cm0.25 cm0.16 cm325 g/cm3

Data Table 6. Displacement Method.

ObjectMass (g)Initial volume of graduated cylinder (mL)Final volume of graduated cylinder (mL)Object Volume (mL)Density (g/mL)
Magnet4 g8 ml10 ml2 ml2g/ml
Metal bolt7.6 g8 ml12 ml4 ml1.9g/ml

Data Table 7. Archimedes’ method.

ObjectMass (g)Mass of Displaced Water (g)Volume of Displaced Water (mL)Density (g/mL)
Metal Bolt7.6 g117.5 g116.4 ml1.07g/ml
Magnet4 g117.1 g116.4 ml1.04 g/ml


Questions

  1. The unknown, rectangular object is 3.6 cm in height, 4.21 cm in length, and 1.17 cm in width. Suppose that the mass is 21.3 g. What is the density of this substance (in grams per milliliter)?

** 1 gram = 1 cm 3.6 x 4.21 x 1.17 = 17.7 21.3g / 17.7mL = 1.2 g/mL The density is 1.2 g/mL

A sample of gold (Au) has a mass of 26.15 g. Since the theoretical density is 19.30 g/mL, what is the volume of the gold sample?

** Volume = Mass/Density Volume- 26.15 g /19.30 g/mL = 1.4 mL

  1. What would occur if you dropped the object into the beaker using the Archimedes Principle method instead of dropping the object into the beaker?

** In case you dropped an object in the beaker, but instead of submerging the object, you used the Archimedes Principle method. I think I would have the same result as the volume of the object, instead of a result that would be based on the buoyancy.

  1. How did the measurement of the density of the magnet by the Principle of Archimedes compare to measuring the density of the magnet by the calculated volume? What is the approach that could be more correct? Why?

** The measurements of the densities are nearly fifty percent less. The Archimedes Principle, the magnet, and the metal bolt seemed to have a lower density. The displacement method appeared to be more accurate because I did not hold the string to each submerged object. There is a great likelihood of human error.

  1. You are presented with a little piece of gold colored material and would like to know whether it is really gold. Applying the Archimedes Principle, you will find the volume of 0.40 cm 3 and the mass of 6.0 g. What inferences can you draw from your bare density analysis?

** To determine the authenticity, I would first find the actual density of gold (19.3 g/cm3 ) and then compute the density of the colored gold material and compare it to the density of the gold to verify authenticity. The numbers given for the gold colored object would make its density 15 g/cm3. I would then conclude that the gold colored object is not gold.

Exercise 3: Concentration, Solution, and Dilution

Data Table 8. Initial Concentration.

ChemicalMass ofVolumetric FlaskMass of Sugar (g)Molar Mass (g)Moles in a Volumetric FlaskTotal Volume (L)Molarity (mol/L)
Sugar (C12H22O11)27.38342.296 g0.0797550.0253.1902mol/L

Data Table 9. Dilution Series.

DilutionVolume (mL)Mass (g)Density (g/mL)Initial Concentration (M)Volume Transferred (mL)Final Concentration (M)
025.0 mL27.7g1.108g/mL 0 mL3.1902 M
125.0 mL24.9g0.996g/mL3.1902 M2.5 mL0.31902 M
225.0 mL25.4g0.984g/mL3.1902 M4.5 mL1.741444 M
325.0 mL25.11.004g/mL3.1902 M3.0 mL2.612166 M
425.0 mL25.61.024g/mL3.1902 M6.0 mL1.306083 M

Data Table 10. Molarity vs. Density.

Molarity vs. Density

Questions

What would prepare 10 mL of a solution of HCl with a concentration of 0.25M, if 1M HCl is available? What is the required amount of 1M HCl? What is the amount of distilled water?

0.25M is 0.25 moles/L 0.25*10/1= 2.5 mL needed

  1. From the graph of Molarity vs. Density, created in Data Table 10, what was the relationship between the molarity of the sugar solution and the density of the sugar solution?

**The less the density of the sugar solution, the less the molarity. It was the same way round.

Leave a Comment

Your email address will not be published. Required fields are marked *

Please Fill The Following to Resume Reading

    Please enter correct phone number and email address to receive OTP on your phone & email.

    Privacy PolicySMS Terms And Conditions

    Verification is required to prevent automated bots.
    Please Fill The Following to Resume Reading

      Please enter correct phone number and email address to receive OTP on your phone & email.

      Privacy PolicySMS Terms And Conditions

      Verification is required to prevent automated bots.
      Scroll to Top