experiment 22 pre laboratory assignment
Experiment #22 Pre-Lab Assignment 0.0015 M Ksp=( x ) (2 x )2=( x ) (4 x2)=4 x3 Ksp=4 (0.001 53)=1.4 ×10−8 The molar solubility of lead (II) iodide will decrease and shift to the left, because extra products will be added. Thus, the equation will compensate for this added amount of products. The purpose of […]










